Drifters R

Bush Bush Grass Grass Wood Wood

1
Black Green Orange Red Yellow

10 2 2 5 1
2
Black Green Orange Red

6 6 4 4
3
Black Green Orange Red Yellow

5 5 2 5 3
4
Black Green Red Yellow

4 5 9 2
5
Black Green Orange

7 10 3
6
Black Green

10 10

Analysis
As some of the results are less than 3; we will combine results of Yellow snails with Green snails and Orange with Red snails.

	B	G + Y	O + R	Total
Population 1 (Bush)	16 Expected = 14 Chi-sq = 0.286	9 Expected = 44/3 Chi-sq = 2.189	15 Expected = 11 1/3 Chi-sq = 1.186	40
Population 2 (Grass)	9 Expected = 14 Chi-sq = 1.786	15 Expected = 44/3 Chi-sq = 0.007576	16 Expected = 11 1/3 Chi-sq = 98/51	40
Population 3 (Wood)	17 Expected = 14 Chi-sq = 9/14	20 Expected = 44/3 Chi-sq = 64/33	3 Expected = 11 1/3 Chi-sq = 625/102	40
	42	44	33	120

X^2 = 16.086 (3 d.p.)
Degree of Freedom = 4
P-value = 0.00290591

Therefore, there is a 0.00290591 chance that we would get the results if the null hypothesis is true.

Critical value (2-tailed) = 9.49
Our results are significant as the Chi-square value is greater than the critical value.